MATH SOLVE

2 months ago

Q:
# WILL GIVE BRAINLIESTWILL GIVE BRAINLIEST AND 50 pointsout of a port departed a steam boat with a speed of 36.8km/h. In 1.75 hours out of the same port and going the Sam direction departed a speed boat. In 1.8 hours after the the department of the speed boat, the distance between the speed boat and the steam boat was 86.9km(behind the steam boat)What was the speed boats speed in km/h?

Accepted Solution

A:

We have the following kinematic equations that model the problem:

steam boat:

r1 = (36.8) * t

speed boat:

r2 = v * (t-1.75)

The distance between the boats is:

d = r2-r1 = v * (t-1.75) - (36.8) * t

Substituting t = 1.8 and d = 86.9 we have:

86.9 = v * (1.8-1.75) - (36.8) * 1.8

We clear the speed:

v = (86.9 + (36.8) * 1.8) / ((1.8-1.75))

v = 3062.8 Km / h

Answer:

the speed boats speed in km / h is:

v = 3062.8 Km / h

steam boat:

r1 = (36.8) * t

speed boat:

r2 = v * (t-1.75)

The distance between the boats is:

d = r2-r1 = v * (t-1.75) - (36.8) * t

Substituting t = 1.8 and d = 86.9 we have:

86.9 = v * (1.8-1.75) - (36.8) * 1.8

We clear the speed:

v = (86.9 + (36.8) * 1.8) / ((1.8-1.75))

v = 3062.8 Km / h

Answer:

the speed boats speed in km / h is:

v = 3062.8 Km / h